Integrand size = 21, antiderivative size = 300 \[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx=\frac {\sqrt {b} \arctan \left (\frac {\sqrt {4 b^2+a^2 d} x}{\sqrt {a} \sqrt {b} \sqrt {4+d x^4}}\right )}{2 \sqrt {a} \sqrt {4 b^2+a^2 d}}-\frac {\sqrt [4]{d} \left (2+\sqrt {d} x^2\right ) \sqrt {\frac {4+d x^4}{\left (2+\sqrt {d} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right ),\frac {1}{2}\right )}{2 \sqrt {2} \left (2 b-a \sqrt {d}\right ) \sqrt {4+d x^4}}+\frac {\left (2 b+a \sqrt {d}\right ) \left (2+\sqrt {d} x^2\right ) \sqrt {\frac {4+d x^4}{\left (2+\sqrt {d} x^2\right )^2}} \operatorname {EllipticPi}\left (-\frac {\left (2 b-a \sqrt {d}\right )^2}{8 a b \sqrt {d}},2 \arctan \left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right ),\frac {1}{2}\right )}{4 \sqrt {2} a \left (2 b-a \sqrt {d}\right ) \sqrt [4]{d} \sqrt {4+d x^4}} \]
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Time = 0.14 (sec) , antiderivative size = 300, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {1231, 226, 1721} \[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx=\frac {\sqrt {b} \arctan \left (\frac {x \sqrt {a^2 d+4 b^2}}{\sqrt {a} \sqrt {b} \sqrt {d x^4+4}}\right )}{2 \sqrt {a} \sqrt {a^2 d+4 b^2}}-\frac {\sqrt [4]{d} \left (\sqrt {d} x^2+2\right ) \sqrt {\frac {d x^4+4}{\left (\sqrt {d} x^2+2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right ),\frac {1}{2}\right )}{2 \sqrt {2} \sqrt {d x^4+4} \left (2 b-a \sqrt {d}\right )}+\frac {\left (\sqrt {d} x^2+2\right ) \sqrt {\frac {d x^4+4}{\left (\sqrt {d} x^2+2\right )^2}} \left (a \sqrt {d}+2 b\right ) \operatorname {EllipticPi}\left (-\frac {\left (2 b-a \sqrt {d}\right )^2}{8 a b \sqrt {d}},2 \arctan \left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right ),\frac {1}{2}\right )}{4 \sqrt {2} a \sqrt [4]{d} \sqrt {d x^4+4} \left (2 b-a \sqrt {d}\right )} \]
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Rule 226
Rule 1231
Rule 1721
Rubi steps \begin{align*} \text {integral}& = \frac {(2 b) \int \frac {1+\frac {\sqrt {d} x^2}{2}}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx}{2 b-a \sqrt {d}}-\frac {\sqrt {d} \int \frac {1}{\sqrt {4+d x^4}} \, dx}{2 b-a \sqrt {d}} \\ & = \frac {\sqrt {b} \tan ^{-1}\left (\frac {\sqrt {4 b^2+a^2 d} x}{\sqrt {a} \sqrt {b} \sqrt {4+d x^4}}\right )}{2 \sqrt {a} \sqrt {4 b^2+a^2 d}}-\frac {\sqrt [4]{d} \left (2+\sqrt {d} x^2\right ) \sqrt {\frac {4+d x^4}{\left (2+\sqrt {d} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right )|\frac {1}{2}\right )}{2 \sqrt {2} \left (2 b-a \sqrt {d}\right ) \sqrt {4+d x^4}}+\frac {\left (2 b+a \sqrt {d}\right ) \left (2+\sqrt {d} x^2\right ) \sqrt {\frac {4+d x^4}{\left (2+\sqrt {d} x^2\right )^2}} \Pi \left (-\frac {\left (2 b-a \sqrt {d}\right )^2}{8 a b \sqrt {d}};2 \tan ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right )|\frac {1}{2}\right )}{4 \sqrt {2} a \left (2 b-a \sqrt {d}\right ) \sqrt [4]{d} \sqrt {4+d x^4}} \\ \end{align*}
Result contains complex when optimal does not.
Time = 10.12 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.22 \[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx=-\frac {i \operatorname {EllipticPi}\left (-\frac {2 i b}{a \sqrt {d}},i \text {arcsinh}\left (\frac {\sqrt {i \sqrt {d}} x}{\sqrt {2}}\right ),-1\right )}{\sqrt {2} a \sqrt {i \sqrt {d}}} \]
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Result contains complex when optimal does not.
Time = 1.05 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.29
method | result | size |
default | \(\frac {\sqrt {2}\, \sqrt {1-\frac {i \sqrt {d}\, x^{2}}{2}}\, \sqrt {1+\frac {i \sqrt {d}\, x^{2}}{2}}\, \Pi \left (\frac {\sqrt {2}\, \sqrt {i \sqrt {d}}\, x}{2}, \frac {2 i b}{\sqrt {d}\, a}, \frac {\sqrt {-\frac {i \sqrt {d}}{2}}\, \sqrt {2}}{\sqrt {i \sqrt {d}}}\right )}{a \sqrt {i \sqrt {d}}\, \sqrt {d \,x^{4}+4}}\) | \(86\) |
elliptic | \(\frac {\sqrt {2}\, \sqrt {1-\frac {i \sqrt {d}\, x^{2}}{2}}\, \sqrt {1+\frac {i \sqrt {d}\, x^{2}}{2}}\, \Pi \left (\frac {\sqrt {2}\, \sqrt {i \sqrt {d}}\, x}{2}, \frac {2 i b}{\sqrt {d}\, a}, \frac {\sqrt {-\frac {i \sqrt {d}}{2}}\, \sqrt {2}}{\sqrt {i \sqrt {d}}}\right )}{a \sqrt {i \sqrt {d}}\, \sqrt {d \,x^{4}+4}}\) | \(86\) |
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\[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx=\int { \frac {1}{\sqrt {d x^{4} + 4} {\left (b x^{2} + a\right )}} \,d x } \]
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\[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx=\int \frac {1}{\left (a + b x^{2}\right ) \sqrt {d x^{4} + 4}}\, dx \]
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\[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx=\int { \frac {1}{\sqrt {d x^{4} + 4} {\left (b x^{2} + a\right )}} \,d x } \]
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\[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx=\int { \frac {1}{\sqrt {d x^{4} + 4} {\left (b x^{2} + a\right )}} \,d x } \]
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Timed out. \[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4+d x^4}} \, dx=\int \frac {1}{\left (b\,x^2+a\right )\,\sqrt {d\,x^4+4}} \,d x \]
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